Why volume of sphere=4/3πr3
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The volume of sphere can be determined by intergration.
Consider an onion like sphere of radius R. Let it have an infinite amount of shells.
Let radius of one such shell be 'r' and its thickness be 'dr'
Surface Area of a sphere = 4πr^2
Therefore volume of the sphere we are considering is
dV = 4πr^2 * dr
Intergrate this equation from the lower limit '0' (the least radius) and R (the largest possible radius of a shell)
V = (4/3)*πr^3.
Hence the formula is derived. However this method requires understanding of Differentitation and Integration, one will learn about these concepts in 11th or so, and will be able to understand it correctly.
Consider an onion like sphere of radius R. Let it have an infinite amount of shells.
Let radius of one such shell be 'r' and its thickness be 'dr'
Surface Area of a sphere = 4πr^2
Therefore volume of the sphere we are considering is
dV = 4πr^2 * dr
Intergrate this equation from the lower limit '0' (the least radius) and R (the largest possible radius of a shell)
V = (4/3)*πr^3.
Hence the formula is derived. However this method requires understanding of Differentitation and Integration, one will learn about these concepts in 11th or so, and will be able to understand it correctly.
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