Question

why we calculate resistance of two bulbs in series circuit by 'r=v²/p', when 'v' will not be same for both the bulbs in series circuit?​

Answer 1

Answer:

Explanation:

There are several useful expressions for power dissipated in a component. These are V * I, I^2 * R and V^2 / R

You have voltage and resistance ratio so the V^2/R expression is suited to answering this:

The ratio of power dissipated in the two bulbs is (V^2 / R) / (V^2 / 2*R) which can be rearranged to (V^2 / R) * (2*R / V^2) = V^2 * 2 * R / V^2 * R = 2:1

In words, this means the low resistance bulb consumes twice the power of the higher resistance bulb.

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