Why we don't use negative base in logarithm?
(-2)^x = 3.
What's x? That is, what power of -2 could give you 3?
You'll either have no answer, or you'll say that it should be the same as the power of 2 that would give you 3.
But that power would be fractional.
And that, is a problem, because a fractional power of a negative number may not be a real number.
The logarithms of non-simple numbers to a negative base can't be defined real-ly, so. Yeah. We just take them out of the equation altogether.
If you still don't get it, comment below.
Answers
Answered by
2
log of negative base is not defined.
it is due to if you will notice the graph of log x when its value on x axis does not crosses the origin in the negative side therefore it is not defined for the negative base
it is due to if you will notice the graph of log x when its value on x axis does not crosses the origin in the negative side therefore it is not defined for the negative base
Attachments:
Answered by
0
Answer:
Step-by-step explanation:
the logarithm function is defined Only for strictly positive numbers.
Similar questions
By definition, you'd know that a^b = c, implies log of c to the base a is b.
Now, if a were negative, say (by your example, if you don't mind) -2, (-2)^b = c, implies log of c to the base (-2) is b.
But consider these:
(-2)^2 = 4. (2)^2 = 4.
Okay, it isn't a major problem...