History, asked by Anonymous, 1 year ago

why were the klungs of java known as comunittie of skilled forest cutters

Answers

Answered by StarrySoul
3
Which class question is this?
Answered by SarcasticAngel
4

Solution :

a) Hydrogen sulphide gas burns in air to give water and Sulphur dioxide

→ Here,

• Reactants : Hydrogen Sulphide and Oxygen

• Products : Water and Sulphur Dioxide

Equation formed :

\sf \: H_2S(g) + O_2 (g)\rightarrow \: H_2 O (l)+ SO_2(g)H

2

S(g)+O

2

(g)→H

2

O(l)+SO

2

(g)

Balanced Equation :

\sf \: 2H_2S(g) + 3O_2 (g)\rightarrow \: 2H_20 (l)+ 2SO_2(g)2H

2

S(g)+3O

2

(g)→2H

2

0(l)+2SO

2

(g)

b) Phosphorus burns in oxygen to give Phosphorus pentoxide

→ Here,

• Reactants : Phosphorus and Oxygen

• Product : Phosphorus Pentoxide

Equation formed :

\sf P(s) + O_{2} (g) \longrightarrow P_{4} O_{10} (s)P(s)+O

2

(g)⟶P

4

O

10

(s)

Balanced Equation:

\sf P_{4} (s) + 5O_{2} (g) \longrightarrow 2P_{2} O_{5}P

4

(s)+5O

2

(g)⟶2P

2

O

5

c) Carbon disulfide burns in air to give carbon dioxide and Sulphur dioxide

→ Here,

• Reactants : Carbon disulfide and oxygen

• Products : Carbon Dioxide and Sulphur Dioxide

Equation formed :

\sf \: CS_2(g) + O_2(g) \rightarrow CO_2(g) + S_20 (g) \:CS

2

(g)+O

2

(g)→CO

2

(g)+S

2

0(g)

Balanced Equation :

\sf \: CS_2(g) + 3O_2(g) \rightarrow CO_2(g) + 2S_20 (g) \:CS

2

(g)+3O

2

(g)→CO

2

(g)+2S

2

0(g)

d) Aluminium metal replaces iron from ferric oxide giving Aluminium oxide and iron.

→ Here,

• Reactants : Aluminum and Ferric Oxide

• Products : Aluminum Oxide and Iron

Equation formed :

\sf \: Al(s) + Fe_2O_3(s) \rightarrow Al_2O_3(s) + Fe (s)Al(s)+Fe

2

O

3

(s)→Al

2

O

3

(s)+Fe(s)

Balanced Equation :

\sf \: 2Al(s) + Fe_2O_3(s) \rightarrow Al_2O_3(s) + 2Fe (s)2Al(s)+Fe

2

O

3

(s)→Al

2

O

3

(s)+2Fe(s)

e) Barium Chloride reacts with zinc sulphate to give zinc chloride and Barium sulphate.

→ Here,

• Reactants : Barium Chloride and Zinc Sulphate

• Products : Zinc Chloride and Barium Sulphate

Equation formed :

\sf \: BaCl_2(s) + ZnSO_4(s) \rightarrow ZnCl_2(s) + BaSO_4(s)BaCl

2

(s)+ZnSO

4

(s)→ZnCl

2

(s)+BaSO

4

(s)

This equation is already balanced.

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