Why x + 1= 0 in this?
In question 1 (I)
Challenge to everyone
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o is the answer mam and iam the winner of challenge
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Step-by-step explanation:
By the Remainder Theorem, we know that
p(x) when divided by (x-a) where a is any real number the Remainder is p(a)
Here we replace the divisor by its "0" >> x-a = 0
That's the reason why x+1 Is 0
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