Physics, asked by shreya200204, 11 months ago

WI
8.
Same spring is attached with 2 kg, 3 kg and 1 kg blocks in three different cases as shown in figure. If
X1, X2 and xg be the extensions in the spring in these cases then (Assume all the blocks to move with
uniform acceleration)
INTIMI
000
00000
X
(A) X, = 0, X3 > X2
2kg 2kg
(B) x2 > X, > X3
3kg 2kg 1kg 2kg
(C) X3 > X1 > X2
(D) X, > X2 > X3​

Answers

Answered by poonambhatt213
76

Answer:

Explanation:

=>Suppose, the tension in the string in which spring is attached to 2 kg block is T₁

T₁ = 2m₁m₂g / m₁ + m₂

= 2 * 2 * 2 / 2 + 2

= 8 / 4

= 2 g

=>Similarly, the tension in the string in which spring is attached to 3 kg block is T₂

T₂ = 2 * 3 * 2 / 3 + 2

= 12 / 5

= 2.4 g

=> Let the tension in the string in which spring is attached to 1 kg block is T₃.

T₃ = 2 * 1 * 2 / 1 + 2

= 4 / 3

= 1.33 g

So, T₂(2.4 g) > T₁ (2 g) > T₃ (1.33 g)

But,  x ∝ T

Thus, x₂ > x₁ > x₃

Therefore, option (B) x₂ > x₁ > x₃ is the correct answer.

Answered by srikanth00715
13

Answer:

Option B is the correct answer

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