Question

Width of class interval x-y is 25 possible value of x and y is

Answer 1

Answer:

Let Lower Limit be L

∴ Upper Limit =L+10 [ Since, Class Width =10]

Now, we know that

ClassMark=(LowerLimit+UpperLimit)÷2

∴ (L+L+10)÷2=25 [Class Mark 25 given]

⇒ 2L+10=50

⇒ 2L=40

⇒ L=20

∴ Lower Limit of the class =20

Upper Limit of the class =20+10=30

The required class is 20−30

Step-by-step explanation:

sorry if answer is wrong