Width of rectangle increases. 25 percent and length doesn't by
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Width of rectangle increases. 25 percent and length doesn't by
solution:
let breadth = 100%b and length = 100%l
area of rectangle = length × breadth = 100%l × 100%b = 10000%lb
Width of rectangle increases. 25 percent
so,25% increase breadth = 100%b +25% of 100% b = 100%b + 25%b = 125%b
area of rectangle with 25% increase in breadth = 25% increase breadth × length = 125%b + 100%l = 12500% lb
so, increase in area = (area of rectangle with 25% increase in breadth) - (area of rectangle before increase) = 12500% lb - 10000% lb = 2500% lb = (2500 × lb )/100 = 25lb
so, increase in area of rectangle is 25lb or 2500% lb of 10000% lb
solution:
let breadth = 100%b and length = 100%l
area of rectangle = length × breadth = 100%l × 100%b = 10000%lb
Width of rectangle increases. 25 percent
so,25% increase breadth = 100%b +25% of 100% b = 100%b + 25%b = 125%b
area of rectangle with 25% increase in breadth = 25% increase breadth × length = 125%b + 100%l = 12500% lb
so, increase in area = (area of rectangle with 25% increase in breadth) - (area of rectangle before increase) = 12500% lb - 10000% lb = 2500% lb = (2500 × lb )/100 = 25lb
so, increase in area of rectangle is 25lb or 2500% lb of 10000% lb
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