width of the river is 5km and it is flowing with the speed of 2m/s the velocity of swimming is 10m/s and he jump in the direction perpendicular to the river flow then find the drift and time taken by swimmer to cross the river
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Answer:
time is 5/root96
drift is 10/root96
Explanation:
first calculate the actual velocity with which swimmer is swimming.
=root10²-2²
=root96.
time is distance / speed.
5/root96
drift would be 2×5/root 96
10root86
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