Physics, asked by riya12367, 1 year ago

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10. Concentration of the Ag* ions in a satural: (3) di
solution of Ag,C,0, is 2.2 x 10-4 mol L
Solubility product of Ag,C,0, is [NEET-2017 17/
17 18 th
(1) 2.42 x 10-8 (2) 2.66 x 10-12
N2(9)
(3) 4.5 * 10-11 (4) 5.3× 10-12
2018]
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Answers

Answered by Azadbirsingh
2

Answer:

Explanation:

Concentration of the Ag+ ions in a saturated solution of Ag2C2O4 is 2.2 x 10-4 mol L-1. Solubility product of Ag2C2O4 is :

Option 1) 2.42 x 10-8 Option 2) 2.66 x 10-12 Option 3) 4.5 x 10-11 Option 4) 5.3 x 10-12

1

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S Sabhrant Ambastha

Answered 1 year, 5 months ago

Solubility product constant -

e.g.

BaSO_{4}\rightleftharpoons Ba^{2+}(aq)+SO_{4}^{2-}(aq)

K=\frac{[Ba^{2+}]\:[SO_{4}^{2-}]}{[BaSO_{4}]}

- wherein

For a pure solid substance the concentration remain constant

\therefore \:K_{sp}=K[BaSO_{4}]

=[Ba^{2+}]\:[SO_{4}^{2-}]

K_{sp}=solubility\:product

Ag_{2}C_{2}O_{4}\rightleftharpoons 2Ag^{+}+C_{2}O_{4}^{2-}

[Ag^{+}]=2[C_{2}O_{4}^{2-}]=2.2\times 10^{-4}

=[C_{2}O_{4}^{2-}]=1.1\times 10^{-4}

K_{sp}=[Ag^{+}]^{2}[C_{2}O_{4}^{2-}]

=\left ( 2.2\times 10^{-4} \right )^{2}\left ( 1.1\times 10^{-4} \right )

=5.324\times 10^{-12}

Option 1)

2.42 x 10-8

This is incorrect option

Option 2)

2.66 x 10-12

This is incorrect option

Option 3)

4.5 x 10-11

This is incorrect option

Option 4)

5.3 x 10-12

This is correct option

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