WILL AN OBJECT OF DENSITY P FLOAT IN A FLUID OF DENSITY 1.5 P?IF YES,WHAT FRACTION OF THE OBJECT VOLUME WILL REMAIN ABOVE THE FLUID?
ANS.=YES,1/3
Answers
Answered by
23
yes.
reason is , an object can float on another object ( fluids ) if the floating object's density is less than the another object.
densities of two objects = P and 1.5P
P = density of object
1.5 P =density of fluid.
as we kniw that , density = mass/volume
volume = mass/ density
ratios of volumes =
volume1. mass1. mass2
______ =_______ ÷ _____
volume2. density 1. density 2
mass1. P
_____×____
1.5P. mass2
P×1/1.5P
=1/1.5
= 1/3
reason is , an object can float on another object ( fluids ) if the floating object's density is less than the another object.
densities of two objects = P and 1.5P
P = density of object
1.5 P =density of fluid.
as we kniw that , density = mass/volume
volume = mass/ density
ratios of volumes =
volume1. mass1. mass2
______ =_______ ÷ _____
volume2. density 1. density 2
mass1. P
_____×____
1.5P. mass2
P×1/1.5P
=1/1.5
= 1/3
Beauty1999:
1/1.5=10/15=2/3
Answered by
13
Answer:
yes , 1/3
Explanation:
we know,
if density of liquid is greater then solid will float on water as upthrust or buoyant force applied by the liquid is greater than the weight of solid.
solution=>>>>>>>>>>
we know,
=>density of solid/density of liquid=immersed volume of the body/total volume of the body
=>here we are using "d" as a sign for density,
let "x"volume of solid is immersed in liquid,and "v" be the total volume of solid.
=>d(s)/d(l)=x/v
=>d/1.5d=x/v
1/1.5=x/v
x=(1/1.5)×v
vol of solid immersed in liquid =(1/1.5)v
vol remained above the liquid=total vol - vol immersed
=> v - (1/1.5)v
=>v - (2/3)v
=>1/3v
answer hope it helps you plz mark brainliest
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