Question

will anyone explain me how to solve this.
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Answer 1

Explanation:

Given : Q is same for object A and B

T¹ for object A is 3°C

T² for object B is 5°C

Mass is 1 g for each object

To find : c

Sol : Q = Mc∆T

= 1 x c x 2

c = 3 J

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Answer 2

Specific heat (C) is defined as the heat to be supplied to increase the temperature of a substance of mass 1 kg through 1° C

∴Heat supplied=mCΔT (where m is mass, C is specific heat and ΔT(final temp-initial temp) is increase in temperature)

Let specific heat of A be C and that of B be C'

As heat supplied is equal in both cases,

H=1*C*3=1*C'*5

C=$\frac{5}{3}$C'

As 5/3>1, The specific heat of A is 5/3 times greater then that of B which means A requires 5/3 times more heat than B to undergo the same increase in temperature

(Always remember- ΔT is the change in temperature, so it can be in Kelvin or Celsius doesn't matter)

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