Question

Will anyone help me in solving this question? It's from the Chapter Exponents and Powers. You've to find the value of x. I demand a step-by-step Answer ​

Answer 1

Step-by-step explanation:

{(2/5^2x4 )x + 2} ={ ( 2/5^-2x+1 )-3}

{2/5^8x + 16} = {2/5^6x -3 }

2/5 = (8x +16 - 6x - 3 )

2/5 = 2x + 13

2 X 13 /5 = 2x

26/5 = 2x

26 /5 X 2 = x

26/10 = x

13/5 = x

I. e x = 13/5

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Answer 2

Answer:

x = -11

Step-by-step explanation:

=> (((2/5)^2)^4)^{x+2} = (((2/5)^{-2})^{x-1})^{-

=> {2}{5}^{8(x+2)} = {2}{5}^{6(x-1)}

=> As the bases are same(2/5) we compare the powers.

=> 8(x+2) = 6(x-1)

=> 8x + 16 = 6x - 6

=> 2x = -22

=> x = -11.

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