Question

will be 2:3
16. The ratio of ages of two persons is 7:11. Seven years hence, the ratio of their
ages
Find their present ages.​

Answer 1

Step-by-step explanation:

The ages of two persons are in the ratio 5:7. Eighteen years ago their ages were in the ratio 8:13. What are their present ages?

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Their present ages is 50 and 70.

Let Ages of two persons is 5x,7x

Eighteen years ago their ages were (5x-18),(7x-18) Their ratio is 8:13 so…

(5x-18)/(7x-18)=8/13

13(5x-18)=8(7x-18)

65x-234=56x-144

65x-56x=234–144

9x=90

x=10

Therefore their ppresent ages will be,

5(10),7(10)

50,70

Answer 2

Answer:

l

Let the age be 7x and 11x

after 7 years

$\frac{7x + 7}{11x + 7} = \frac{2}{3} \\ 21x + 21 = 22x + 14 \\ x = 7$

so ages are 49 and 77 years