Question

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Answer 1

cotA -cosA)/(cotA + cosA) = (cosecA-1)/(cosecA+1)

(cotA -cosA)/(cotA + cosA)

((cosA/sinA)-cosA)/((cosA/sinA)-cosA) since cotA=cosA/sinA

taking cosA common from numretor nd denominatr nd cancelling it we get

((1/sinA)-1)/((1/sinA)+1) since 1/sinA=cosecA

therfore

(cosecA-1)/(cosecA+1)

Answer 2

Answer:

Step-by-step explanation:

LHS=cosA/sinA-cos A/cosA/sinA+Costa

=cosA(1/sinA-1)/cosA(sinA+1)

=cosecA-1/cosecA+1(since 1/sinA=cosecA)

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