Will depression in freezing point be same or different if 0.1mole of sugar or 0.1 mole of glucose is dissolve in one litre of water.
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So, here is the solution to the question.
⧍T ∝ molality
molality=mole solute/weight solvent
weight of solvent=density*volume=1000*1 kg
⧍T ∝ moles
moles =given mass(m)/molecular mass(M)=0.1/M
M of sugar(sucrose)=342
M of glucose=180
⧍T∝1/M
⧍T(sugar)/⧍T(glucose)=[1/M(sugar)]/[1/M(glucose)]=180/342<1
So, in this case therefore,
⧍T(sugar)/⧍T(glucose)<1
⧍T(sugar)<⧍T(glucose)
Hence, it is proved that the depression in freezing point in glucose will be more and will be not same. It will be less in sugar.
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