Question

Will depression in freezing point be same or different if 0.1mole of sugar or 0.1 mole of glucose is dissolve in one litre of water. ​

Answer 1

Answer:

So, here is the solution to the question.  

⧍T ∝ molality

molality=mole solute/weight solvent

weight of solvent=density*volume=1000*1 kg

⧍T ∝ moles

moles =given mass(m)/molecular mass(M)=0.1/M

M of sugar(sucrose)=342

M of glucose=180

⧍T∝1/M

⧍T(sugar)/⧍T(glucose)=[1/M(sugar)]/[1/M(glucose)]=180/342<1

So, in this case therefore,

⧍T(sugar)/⧍T(glucose)<1

⧍T(sugar)<⧍T(glucose)

Hence, it is proved that the depression in freezing point in glucose will be more and will be not same. It will be less in sugar.