Question

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Let ​ f(x)=x2+17x+72 ​ . What are the zeros of the function? ​Enter your answers in the boxes. ​

Answer 1

x = -17 +- √289-4*72*1/2*1
x = -17 +- 1 /2
x = -18/2 = -9
x = -16/2 = -8
x= -9 , -8
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