Question

WILL GIVE BRAINLIEST - FOR ENGLISH 3 (NOVEL: The Great Gatsby by F. Scott Fitzgerald)


COMPARISON/ CONTRAST LITERARY ANALYSIS OUTLINE

THESIS STATMENT:





I. Main Idea for 1st Body Paragraph (Choose a literary element used in both texts.)

A. Literary Element use and effect in novel
1. Specific example:
2. Specific example:

B. Literary Element use and effect in 2nd piece of literature
1. Specific example:
2. Specific example:

C. Relation of This Literary Element to the Theme
1. Details from primary/ secondary source:
2. Details from primary/ secondary source:

II. Main Idea for 2nd Body Paragraph (Choose a literary element used in both texts.)

A. Literary Element use and effect in novel
1. Specific example:
2. Specific example:

B. Literary Element use and effect in 2nd piece of literature
1. Specific example:
2. Specific example:

C. Relation of This Literary Element to the Theme
1. Details from primary/ secondary source:
2. Details from primary/ secondary source:

III. Main Idea for 3rd Body Paragraph (Choose a literary element used in both texts.)

A. Literary Element use and effect in novel
1. Specific example:
2. Specific example:

B. Literary Element use and effect in 2nd piece of literature
1. Specific example:
2. Specific example:

C. Relation of This Literary Element to the Theme
1. Details from primary/ secondary source:
2. Details from primary/ secondary source:

Answer 1

${\orange{\bigstar}} \ {\underline{\green{\textsf{\textbf{Given :-}}}}}$

Diameter of the circle = 42 m

Cost of cleaning per m² = ₹2.35

${\blue{\bigstar}} \ {\underline{\pink{\textsf{\textbf{To Find :-}}}}}$

Cost of cleaning the whole field

${\red{\bigstar}} \ {\underline{\purple{\textsf{\textbf{Formula Used :-}}}}}$

${\boxed{\green{\textsf{\textbf{Area of a circle = }}} {\blue{\sf{\pi r^2}}}}}$

where,

r = Radius

${\sf{\pi = \dfrac{22}{7}}}$

${\orange{\bigstar}} \ {\underline{\blue{\textsf{\textbf{Solution :-}}}}}$

$Radius = {\sf{\dfrac{Diameter}{2}}}$

$\longmapsto {\sf{\dfrac{42}{2}}}$

$\longmapsto {\sf{21 \ m}}$

${\pink{\textsf{\textbf{Radius = 21 m}}}}$

According to the question by using the formula of Area of a Circle, we get,

$\dashrightarrow \ {\green{\sf{Area \ of \ circular \ field = (\pi \times 21^2) \ m^2}}}$

Solving the above equation,

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21^2 \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21 \times 21 \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 441 \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{{\cancel{7}}^{ \ 1}} \times {\cancel{441}}^{ \ 63} \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{(22 \times 63) \ m^2}}$

$: \ \Longrightarrow \ {\sf{1,386 \ m^2}}$

${\blue{\textsf{\textbf{Area of the circular field = 1,386 sq. m.}}}}$

Cost of cleaning the field = ₹ (1,386 × 2.35)

$: \ \Longrightarrow \ {\sf{\purple{Rs. \ 3257.1}}}$

${\boxed{\orange{\textsf{\textbf{Cost of cleaning the field is Rs. 3257.1}}}}}$