*will give brainliest if you show your work*
One side of a triangle is 15 inches, and the area of the triangle is 90 sq. inches. Find the area of a similar triangle in which the corresponding side is 9 inches.
32.4 sq. in.
54 sq. in.
150 sq. in.
Answers
Answered by
20
now the ratio of area of two similar triangles is equal to the ratio of the squares of their corresponding sides
by the above statement
let x be the area of the second triangle
90/x=(15)^2/(9)^2
90/x=225/81
225x=90x81
x=(90×81)/225
x=32.4
by the above statement
let x be the area of the second triangle
90/x=(15)^2/(9)^2
90/x=225/81
225x=90x81
x=(90×81)/225
x=32.4
fishes:
Correct but you forgot the .4 so the answer is actually 32.4 :)
Answered by
1
54 sq.in.
as..
15 in. is base
Then, 1/2x15xh =90sq.in.
h=12
therefore, 9in. is base and 12in. is height
1/2x9x12=54
as..
15 in. is base
Then, 1/2x15xh =90sq.in.
h=12
therefore, 9in. is base and 12in. is height
1/2x9x12=54
This answer is incorrect. It is 32.4
ohkkk. i got it...sryy
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