Question

will mark as brainliest whomsoever answers it first.
perimeter of two squares are 40 cm and 96 CM respectively find the perimeter of another square
equal in area to the sum of first two .

Answer 1

side 1st 1st = 10 cm
side of 2nd = side = 24 cm
area of square 1st = 10×10 = 100 cm^2
area of 2nd square = 24×24 = 576 cm^2
area = 100 +576 = 676 cm^2"

Answer 2

Perimeter of 1st square is 40
Formula of Perimeter of a square= 4×S
If P = 40,
Side of 1st square = 40 ÷ 4 = 10
In the same way perimeter of 2nd square is 96 ÷ 4 = 24

Formula to find area of a square= S×S
Area of 1st square is 10 × 10 = 100
Area of 2nd square =24×24 = 576
Area of 3rd square = 576+100= 676

Side of 3rd square = root over 676 = 26
Perimeter = 4×S = 4×26= 104cm