Question

will mark as brainlist...4 no need

Answer 1

Answer: The calculations are done below.

Step-by-step explanation:

(1) We have

$(x+1)(x+1)=x^2+2x+1\\\\\Rightarrow x+1=\dfrac{x^2+2x+1}{x+1}.$

So, the remainder is (x+1).

(2) We have

$3^\frac{2}{3}\times 7^\frac{2}{3}=(3\times 7)^\frac{2}{3}=21^\frac{2}{3}.$

(3) We have

$(x-1)(x^2+1+x)=x^3+x+x^2-x^2-1-x=x^3-1.$

(4) Two rational numbers between 3 and 4 are

$3\dfrac{1}{4}=\dfrac{13}{4}~~\textup{and}~~3\dfrac{3}{4}=\dfrac{15}{4}.$

(5) Yes, every integer is rational, because it can be written in the form

$\dfrac{p}{q},~~q\neq 0.$

Thus, all the 5 questions are answered.