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What is the value of the product (3 – 2i)(3 + 2i)?
5
9 + 4i
9 – 4i
13
Well... (3 - 2i)(3+2i) = (3 * 3) + (-2i * 2i) = 9 + -4i^2
i^2 = -1 so we have
9 +-4(-1)
= 9 + 4
= 13
Is my work correct here?
Answers
Answered by
2
hai friend,
(3-2i)(3+2i)
as (a+b)(a-b) =a²-b²
3²-(2i)²
=9-(4*-1)
=9-(-4)
=9+4
=13
hope helped!!
(3-2i)(3+2i)
as (a+b)(a-b) =a²-b²
3²-(2i)²
=9-(4*-1)
=9-(-4)
=9+4
=13
hope helped!!
HappiestWriter012:
brainliest plzz
Answered by
0
9-4i^2
9-4(-1)^2
9-4=5
9-4(-1)^2
9-4=5
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