Question

Will Mark Brainliest
if 10 g of oxygen and 20 g of nitrogen monoxide are present, which substance is the limiting reacant?

What mass of nitrogen dioxide would be produced?

Answer 1

Answer:

oxygen is the limiting reagent in the reaction.

Explanation:

moles of oxygen=10/32

moles of nitrogen=20/28

N2 + 2O2= 2NO2

since O2 is limiting reagent due to less number of moles thus O2 will decide the amount of NO2 formed.

1 mol of oxygen ------ 1 mol of NO2

10/32 mol of oxygen-- 10/32 mol of NO2

= 46*10/32g of NO2

=14.375 g of NO2

Answer 2

Answer:

The answer is that relates to the number of moles of the substance as indicated ...

Explanation:

if 558 kJ of energy are supplied, what mass of NO can be made? ... How many grams of N 2 will react if 100.0 kJ of energy are supplied? ... Its classic reactants are aluminum metal and iron(III) oxide; the reaction produces iron .... 6.60 × 10 2 g.