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Answer:
30cm
Step-by-step explanation:
IN TRIANGLE ABD,
ACC. TO PYTHAGORAS THEOREM
(AD)²+(AB)²=(BD)²
(3)²+(4)²= (BD)²
BD= 5cm
IN TRIANGLE BCD,
ACC. TO PYTHAGORAS THEOREM
(BD)²+ (DC)²= (BC)²
(5)²+(DC)²= (13)²
DC= 12cm
FOR PERIMETER OF BCD,
BD+ DV+ BC
=5+12+13
= 30cm
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