Question

will terminate
21 x 54
2. If the sum of the zeroes of the quadratic polynomial 3x2 – kx + 6 is 3, then find the value of k.
3. For what value of k, the pair of linear equations 3x + y = 3 and 6x + ky = 8 does not have a solution.
4. If 3 chairs and 1 table costs 1500 and 6 chairs and 1 table costs 2400. Form linear equations to
represent this situation,​

Answer 1

Aɴsᴡᴇʀ࿐

Let Z be the number

Z = 13x + 11 where x is the quotient when Z is divided by 13

Z = 17y + 9 where y is the quotient when Z is divided by 17

13x + 11 = 17y + 9

13x + 2 = 17y since x and y are quotients they should be whole numbers . Since y has to be a whole number the left hand side should be multiple of 17

The least possible value of x satisfying the condition is 9 and y will be 7

The answer is 13*9 + 11 = 128 or it is 17*7 + 9 = 128

This is the least number possible. There will be multiple answers and will increase in multiples 17*13 = 221 like 349 , 570, etc.

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Answer 2

Answer:

If the sum of the zeroes of the quadratic polynomial 3x2-kx+6 is 3, then find the value ... For what value of k, the pair of linear equations 3x+y=3 and 6x+ky=8 does.

Step-by-step explanation:

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