Will the following polynomial will be completely divisible by 2x-1

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Answer:
p(x)= 2x^3+(-28x^2)+11x+(-28)+3
=2x^3-28x^2+11x-28+3
=2x^3-28x^2+11x-25
g(x)=2x-1
2x-1=0
2x=1
x=1/2
p(1/2)=2(1/2)^3-28(1/2)^2+11(1/2)-25
=2(1/8)-28(1/4)+11(1/2)-25
=(1/4)-7+(11/2)-25
=1-28+22-100/4. (taking LCM)
=-105/4
=-26.25 -ans
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