Question

.Will the force of gravity is same on a taller person of mass 60 kg and a short person of same mass. Justify.​

Answer 1

Answer:











Home

>

English

>

Class 10

>

Physics

>

Chapter

>

Gravitation

>

What will be the gravitational...

What will be the gravitational force on 60 kg man on the Moon, Mars and Jupiter? Are they the same? Why ? "M (Moon)"=7.36xx10^(22),"kg R(Moon)"=1.74xx10^(6)m, "M (Mars)"=6.4xx10^(23)"kg, R (Mars)"=3.395xx10^(6)m, "J (Jupiter)"=1.9xx10^(27)"kg. R (Jupiter)"=7.15xx10^(7)m, G=6.67xx10^(-11)N.m^(2)//kg^(2)

Updated On: 6-2-2021

Click here to get PDF DOWNLOAD for all questions and answers of this chapter - NAVNEET PUBLICATION - MAHARASHTRA BOARD Class 10 GRAVITATION





Click here to get PDF DOWNLOAD for all questions and answers of this Book - NAVNEET PUBLICATION - MAHARASHTRA BOARD Class 10 PHYSICS



Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.



Text Solution

Open Answer in App

Solution

Data : m1=60kg,m2=7.36×1022kg,m1=60kg,m2=7.36×1022kg,

R=1.74×106m,F=?R=1.74×106m,F=?

F=Gm1m2R2F=Gm1m2R2

=6.67×10−11×N.m2/kg2×60kg×7.36×1022kg(1.74×106m)2=6.67×10-11×N.m2/kg2×60kg×7.36×1022kg(1.74×106m)2

=97.29N=97.29N

On the moon's surface, the gravitational force on the man due to the moon =97.29N.=97.29N.

(2) Data : m1=60kg,m2=6.4×1023kg,m1=60kg,m2=6.4×1023kg,

R=3.395×106m,F=?R=3.395×106m,F=?

F=Gm1m2R2

hope it helps :)

Answer 2

Answer:

Solution : Data : `m_(1)=60kg, m_(2)=7.36xx10^(22)kg,` <br> `R=1.74xx10^(6)m, F = ?` <br> `F=(Gm_(1)m_(2))/(R^(2))` <br> `=(6.67xx10^(-11)xxN.m^(2)//kg^(2)xx60kgxx7.36xx10^(22)kg)/((1.74xx10^(6)m)^(2))` <br> `=97.29N` <br> On the moon's surface, the gravitational force on the man due to the moon `=97.29N.` <br> (2) Data : `m_(1)=60kg, m_(2)=6.4xx10^(23)kg,` <br> `R=3.395xx10^(6)m, F=?` <br> `F=(Gm_(1)m_(2))/(R^(2))` <br> `=(6.67xx10^(-11)N.m^(2)//kg^(2)xx60kgxx6.4xx10^(23)kg)/((3.395xx10^(6)m)^(2))` <br> `=222.2N` <br> On the surface of Mars, the gravitational force on the man due to Mars = 222.2 N. <br> (3) Data : `m_(1)=60kg, m_(2)=1.9xx10^(27)kg,` <br> `R=7.15xx10^(7)m, F=?` <br> `F=(Gm_(1)m_(2))/(R^(2))` <br> `=(6.67xx10^(-11)N.m^(2)//kg^(@)xx60kgxx1.9xx10^(27)kg)/((7.15xx10^(7)m)^(2))` <br> = 1487 N <br> On the surface of Jupiter, hte gravitational force on the man due to Jupiter = 1487 N. <br> Thus, the force on the man are not the same because the ratio `(M//R^(2))` is not the same in the case of the moon, Mars nad Jupiter.

Explanation:

mark me as brainlist