Will the mouse and cat be able to meet at one point?
(i) Yes (ii) No
(iii) Incomplete data (iv) Cannot be said
(b) What condition is used to say that mouse and cat will meet at one point?
(i) 1 1
2 2
a b
a b
(ii) 1 1 1
2 2 2
a b c
a b c
(iii) 1 1 1
2 2 2
a b c
a b c
(iv) None
(c) If YES, then after how much time?
(i) 7 sec (ii) 5 sec (iii) 6 sec (iv) 10 sec
(d) If YES, then at what height?
(i) 9m (ii) 19m (iii) 15m (iv) 7m
(e) If the movement of the cat is given by 2s – b = 9 and movement of the mouse is
given by 6s – 3b = 21, then state whether the cat and mouse will meet each other
or not?
(i) Yes (ii) No
(iii) Cannot be said (iv) Data is incomplet
Answers
Given : A computer animation below shows a cat moving in a straight line, its height b meters above the ground is given by 8s - 3b = -9, where 's' is the time in seconds after it starts moving in the same animation, a mouse starts to move at the same time as the cat and its movement is given by -3s + b = 1
To Find : a) Will the mouse and cat be able meet at one point?
After how many seconds they meet?
At what height do they meet?
If the movement of the cat is given by 2s – b = 9 and movement of the mouse is given by 6s – 3b = 21, then state whether the cat and mouse will meet each other or not?
Solution:
Cat movement 8s - 3b = - 9 Eq1
Mouse movement -3s + b = 1 Eq2
8/-3 ≠ - 3/1 Hence unique solution Exist
mouse and cat be able meet at one point - YES
condition is used to say that a mouse and cat will meet at one point
a₁/a₂ ≠ b₁/b₂
Eq1 + 3 * Eq2
=> 8s - 9s = -9 + 3
=> - s = - 6
=> s = 6
-3s + b = 1 => b = 19
Cat and mouse meet after 6 sec at height 19 m
movement of the cat is given by 2s-b=9
movement of the mouse is given by 6s-3b=21
2/3 = -1/-3 ≠ 9/21
Hence cat and mouse will not meet each other
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Answer:
1) a yes
2)a
3)c 6 sec
4)b 15m
5)b no