will there be any friction acting between the surface of the striker and carrom board if the striker is at rest with respect to carrom board
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The distance x which the striker traverses during its motion=(221)2+(221)2=21=0.5m=x
The initial kinetic energy of the striker goes into the heat emitted due to work done against friction.
⟹21mv2=μmgs
⟹s= Total distance traveled by the striker=2μgv2
=2×0.2×104=1m=2x
Thus the striker stops at the mid point of the top side.
The coordintates of that point with respect to the origin=(221,21).
hope it help u
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