Question

Will you plz send me solutions of question no. 4

Answer 1

Answer:

distance is 50+75

=125m

average speed

=50+75/2

=125/2

=62.5m/s

so accelaration is

=62.5m

Explanation:

#Be Brainly

Answer 2

u=0,a (uniform acceleration),t=n

v (final velocity after n seconds)

v=0+an⟹v=an⟶(1)

s  

n

​  

 (distance travelled in n seconds)=0+  

2

1

​  

an  

2

 

s  

n−2

​  

=  

2

1

​  

a(n−2)  

2

 

Distance travelled in least 2 seconds       =s  

n

​  

−s  

n

​  

−2

=  

2

1

​  

a[n  

2

−(n−2)  

2

]=  

2

1

​  

a[n  

2

−n  

2

−4+4x]=2an−2a⟶(2)

From equation 1 and 2,

x=2a(n−1)

x=  

u

2v

​  

(n−1)