William place a 37 feet ladder against a wall.If base of ladder 12 feet from base of the wall,how high up the wall will ladder reach?
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Consider a triangle ABC, with B as the right angle.
ATQ,
The length of ladder= 37m. [This is the hypotenuse AC]
& The distance between the building and ladder= 12m [BC]
We need to find AB i.e. the height at which the ladder would reach.
Using Pythagoras Theorem,
We can say that,
AB^2 + BC^2 = AC^2
Therefore,
AB^2= AC^2- BC^2
AB^2= 37^2 - 12^2
AB^2= 1369 - 144
AB^2= 1225
AB= 35m Ans.
ATQ,
The length of ladder= 37m. [This is the hypotenuse AC]
& The distance between the building and ladder= 12m [BC]
We need to find AB i.e. the height at which the ladder would reach.
Using Pythagoras Theorem,
We can say that,
AB^2 + BC^2 = AC^2
Therefore,
AB^2= AC^2- BC^2
AB^2= 37^2 - 12^2
AB^2= 1369 - 144
AB^2= 1225
AB= 35m Ans.
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0
Answer:
35 feet
Step-by-step explanation:
explanation is in the picture
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