Win 10 gram of non volatile solute is dissolved in hundred gram of benzene it raises boiling point by 1 degree celsius then molecular mass of the solute is
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Explanation:
Hey dear....
Delta Tb = Kb *I * m
m = Wsolute /(Msolute*Wsolute in kg
=10/(M2*0.1)
M2=I * Kb * Wsolute /(delta Tb * Wsolute in kg)
= 1*2.52*10/(1*0.1)
=252g/mol
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