wind blowing at the speed of 5 to 8 km per hour
Answers
Answer:
JetStream Max: Beaufort Wind Force Scale
The velocity of wind relative to man = Actual of wind − Actual of man ...(1)
Let i and j represent unit vectors along East and North.
Let the actual velocity of wind be given by xi+yj.
In the 1st case the man's velocity is 8i and that of the wind relative to man being from north is −pj.
∴−pj=(xi+yj)−8i by (1)
Comparing coefficients x−8=0,y=−p ...(2)
In the 2nd case when the man doubles his speed, it seems to come from N-E.
−q(i+j)=(xi+yj)−16i
∴x−16=−q,y=−q...(3)
Putting x=8, we get q=8
∴y=−8
Hence the velocity of wind is xi+yj=8(i−j)
Its magnitude is
(8
2
+8
2
)
=8
2
and tanθ=−1∴θ=−45
∘
,
Hence its direction is from N-W.
Explanation:
hope it helps you
please mark as brainliest
Answer:
3 km
8-5
5×8
40 min
40-3
37