Wire A and B has fundamental frequency 256Hz and 382Hz respectively. How many beats will be heard in two second from third harmonic of A and second harmonic of B.
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SOLUTION
Third harmonic of A
n=256×3=768 Hz
Second harmonic of B
n=382×2=764 Hz
No. of beats / second=n−n'
=768 - 764
=4 × 2Hz
= 8
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Jhani:
But i asked no. Of beats
Yeah so 4 × 2 = 8...okay..thank you
Why u subtracted 768 snd 764?
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