wire A and wire B have the following ratios LA/LB = S/18, Diameter DA/Diameter DB= 2/3 Resistivity pA/Resistivity pB= 4/9 what is the ratio of the resistance of wire A to the resistance of wire B ? a) 5:18 b) 10:54 c) 18:5 d) 54:10
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5/18 .....
by using R=delta /A
RA/RB
delta A Length A/AA/
delta B length B/AB
then delta A/B ✖ length A/B x area A/B
4/5. x5/18 =20/9x18
=9/4
=5/18
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