Question

wire A and wire B have the following ratios LA/LB = S/18, Diameter DA/Diameter DB= 2/3 Resistivity pA/Resistivity pB= 4/9 what is the ratio of the resistance of wire A to the resistance of wire B ? a) 5:18 b) 10:54 c) 18:5 d) 54:10​

Answer 1

Answer:

it will help you.........

Answer 2

Answer:

5/18 .....

by using R=delta /A

RA/RB

delta A Length A/AA/

delta B length B/AB

then delta A/B ✖ length A/B x area A/B

4/5. x5/18 =20/9x18

=9/4

=5/18