Question

wire carrying a current of 140A is bent into e form of a circle of radius 6cm. The flux nsity at a distance of 8 cm on the axis from centre is​

Answer 1

Explanation:

B=

2(a

2

+x

2

)

2

3

μ

0

i⋅a

2

=

(36+8

2

)

2

3

×10

−6

2π×10

−7

×140×36×10

−4

=

1000×10

−6

2π×10

−7

×140×36×10

−4

=π×10

−4

T

Answer 2

Answer:

π×10 power -4T

B = mu0

i·a^22(a^2 + x^2)^ 32

= 2pi × 10^-7 × 140 × 36 × 10^-4

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