WIRE DIAGRAME
VELLDE B.
REAN OM
BLACK GND
PLAY
UN ANY
WONT NOT
PEAKER
PED ACC
FRONT LEFT
SPEAKER
FRONT LEFT
SPEAKER
Rich Jack
ANTI Jack
g
DC Input: 914,4V
Loudspeaker Impendance 40
FM: 87.5 108 MHZ
Attention: The output lines of the amplifire should not be eathing or
colliding. Before installation, please check if the speaker circuit of the
car has any earthing lines. If yes please re-layout the circuit before
connecting to the instrument. Otherwise the amplifire could be damage
Answers
\huge\purple{mark brainliest please}markbrainliestplease
\large{\mathbb{\purple{\boxed{\green{\underbrace{\overbrace{\red{\boxed{\red{♪HLO♪}}}}}}}}}}
♪HLO♪
<br />\sf\huge\bold\red{༄❁❁❁❁❁༄ }༄❁❁❁❁❁༄ HLO GUYS
muje corona ka vaccine mil gya he
agr kis chhai to muje contact kre. (WHO)\sf\huge\bold\purple{༄❁❁❁❁❁༄ }༄❁❁❁❁❁༄
\begin{gathered}name \: the \: colours \: of \: the \: rainbow \\ \end{gathered}
namethecoloursoftherainbow
\huge\underline{\overline{\mid{\bold{\red{Don't..Spam-}}\mid}}}
∣Don
′
t..Spam−∣
\huge\mathtt\purple{\boxed{\underbrace\pink{\overbrace\green{ question}}}}
question
{\blue{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\fbox{\red{??}}}}}}}}}}}}}}}}}}}}}}}}}}}}
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\begin{gathered}\begin{gathered}\begin{gathered}\sf \large \red{\underline{ Question:-}}\\\\\end{gathered}\end{gathered}Question:−\end{gathered}
Question:−
Question:−
The measures of two adjacent angles of a parallelogram are in the ratio 3:2. Find the measure of each of the angles of the parallelogram.
\begin{gathered}\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{Given:-}}\\\\\end{gathered}\end{gathered}Given:−\end{gathered}
Given:−
Given:−
The measures of two adjacent angles of a parallelogram are in the ratio 3:2.
\begin{gathered}\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{To \: Find:-}}\\\\\end{gathered}\end{gathered}ToFind:−\end{gathered}
ToFind:−
ToFind:−
Find the measure of each of the angles of the parallelogram.
\begin{gathered}\begin{gathered}\begin{gathered}\\\\\sf \large \red{\underline{Solution :- }}\\\\\end{gathered}\end{gathered}Solution:−\end{gathered}
Solution:−
Solution:−
\text{ \sf suppose the angles be equal to 3x and 2x} suppose the angles be equal to 3x and 2x suppose the angles be equal to 3x and 2x suppose the angles be equal to 3x and 2x
\boxed{ \sf \orange{ we \: have \: ardjacent \: angles \: of \: a \: parallelogram \: = 180}}wehaveardjacentanglesofaparallelogram=180
wehaveardjacentanglesofaparallelogram=180
wehaveardjacentanglesofaparallelogram=180
\begin{gathered}\begin{gathered}\begin{gathered}\\ \sf \underline{ \green{putting \: all \: values : }}\end{gathered}\end{gathered}puttingallvalues:\end{gathered}
puttingallvalues:
puttingallvalues:
\begin{gathered}\begin{gathered}\begin{gathered}\: \\ \sf \to \: 3x + 2 x = 180\: \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \:5x = 180 \\ \\ \: \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \frac{180}{5} \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \:x \: = \cancel{ \frac{180}{5} } \\ \\ \sf \to \: \: \: \: \: \: \: \: \: \: \purple{x = 36}\\\\\end{gathered}\end{gathered}→3x+2x=180→5x=180→x=5180→x=5180→x=36\end{gathered}
→3x+2x=180
→5x=180
→x=
5
180
→x=
5
180
→x=36
→3x+2x=180→5x=180→x=5180→x=5180→x=36
\begin{gathered}\begin{gathered}\begin{gathered}\sf \to \: 3x \\ \sf \to \: 3 \times 36 \\ \sf \to \red{108 }\\ \\ \\ \sf \to \: 2x \\ \sf \to \: 2 \times 36 \\ \sf \to \orange{72} \\\end{gathered}\end{gathered}→3x→3×36→108→2x→2×36→72\end{gathered}
→3x
→3×36
→108
→2x
→2×36
→72
→3x→3×36→108→2x→2×36→72
\sf \large\underline{ \blue{verification }} \huge \dagverification†
verification
\dagverification†
\begin{gathered}\begin{gathered}\begin{gathered}\\ \\ \sf \to 3x + 2x = 180 \\ \\ \sf \to \: 3 \times 36 +2 \times 36 = 180 \\ \\ \sf \to \: 108 + 72 = 180 \\ \\ \sf \to \:180 = 180 \\ \\ \large \underline{ \pink{ \sf \: hence \: verified}} \huge \dag\end{gathered}\end{gathered}→3x+2x=180→3×36+2×36=180→108+72=180→180=180henceverified†\end{gathered}
→3x+2x=180
→3×36+2×36=180
→108+72=180
→180=180
henceverified
†
→3x+2x=180→3×36+2×36=180→108+72=180→180=180henceverified†