wire has resistance 20 ohm is streached then uts length increase by 10 present then what is new resistance
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Answer:
Explanation:
Given resistance = R1 = 20 ohm
Let length of the wire = L
Therefore, new length of the wire = 2L
Since, when the length is doubled, cross sectional area of the wire becomes half.
Therefore, new resistance = R = 2L/ (A/2) =4L/A
R = 4 x 20 (since, L/A = resistance)
R = 80 ohm.
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