Question

wire is bent to form an equilateral triangle and wire b is bent in the form of a square such that the area covered by the triangle and square is the same what is the ratio of the length of wire a to wire b. ​

Answer 1

Answer:

56vjgshfnxjdgxfudhry

Answer 2

Answer:

346.5cm

Step-by-step explanation:

Area of an equilateral triangle=

4

3

a

2

where a=side of the triangle

Now, given that

4

3

a

2

=121

3

a

2

=121×4

a

2

=484

a=

484

a=22 cm

Therefore,

Length of wire=a+a+a=66 cm

Now, this wire is bent into a circle, so circumference of circle=length of the wire

So,

2πr=66

2×

7

22

×r=66

r=

2×22

66×7

r=

2

21

Now,

Area of circle=πr

2

=

7

22

×(

2

21

)

2

=

2

693

=346.5 cm

2