wire of area of cross-section A is made of metal P and carries current I. If density of the wire is p, mass of an atom of metal P is m and each atom of P contributes one free electron then the correct expression for drift speed of the free electrons is [e charge of an electron]
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Answer:
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Explanation:
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Answer:
Explanation:
Subatomic particles like electrons move in random directions all the time. When electrons are subjected to an electric field they do move randomly, but they slowly drift in one direction, in the direction of the electric field applied. The net velocity at which these electrons drift is known as drift velocity.The SI unit of drift velocity is m/s. It is also measured in m2/(V.s).
The drift velocity of an electron for a unit electric field is known as mobility of the electron.We can define current density as the total amount of current passing through a unit cross-sectional conductor in unit time. From drift velocity, we know the formula for drift velocity as:
I = nAvQ
J = I/A = nVQ
Where,
J is the current density measured in Amperes per square meter
v is the drift velocity of the electrons
Thun, we can say that the drift velocity of the electrons and their current density are directly proportional to each other. Also, when the electric field intensity increases, the drift velocity increases and the current flowing through the conductor also increases.
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