wire of length 1.5 m extends by 0.15 mm when a force is applied to it. Calculate the stress produced in it, if Y = 2 x 1011 N/m2.
Answers
Answer:
The stress produced in the wire is 20 N/m^2.
Explanation:
The stress (σ) produced in a material is defined as the ratio of the force (F) applied to the material to the cross-sectional area (A) of the material. Mathematically,
σ = F / A
In this problem, we are given the length (L) of the wire, the extension (ΔL) produced in the wire, and the Young's modulus (Y) of the material. We can use the following formula to calculate the force (F) applied to the wire:
F = Y * A * ΔL / L
where A is the cross-sectional area of the wire.
We can rearrange this equation to solve for the stress (σ) as follows:
σ = F / A = Y * A * ΔL / (A * L) = Y * ΔL / L
Substituting the given values, we get:
σ = Y * ΔL / L = 2 x 10^11 N/m^2 * (0.15 x 10^-3 m) / 1.5 m
σ = 2 x 10^11 N/m^2 * 0.1 x 10^-3
σ = 20 N/m^2
Therefore, the stress produced in the wire is 20 N/m^2.
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