Question

Wire of length l and mass m is bent to form a semicircle the moment of inertia

Answer 1

Question:

Wire of length l and mass m is bent to form a semicircle the moment of inertia?

Answer:

$l = \pi \: r$

$r = \frac{l}{\pi}$

$symmetry \: m.i \: of \: ring \: about \: y \: and \: y$

$= (2m) \frac{ {r}^{2} }{2}$

$m.i \: of \: half \: ring \: = m( \frac{ {r}^{2} }{2} )$

$= m( \frac{l}{2 {r}^{2} } )$

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