Wire of the same material but double the radius is half the lamborghini again
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l1= L/2. d1=2d
l2=L. d2=d
Y and F is same for both the wires:
increase in length=
FL/AY
1st wire:
increase in length=
F(L/2)/(π2d)²Y
4FL/8πd²Y
FL/2πd²Y
2nd wire : increase in length.
FL/πd²Y
Ratio:
FL/2πd²Y: FL/πd²y
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