Question

Wires of 2 and 3 Q2 resistance are connected in parallel. Find their resultant resistance.​

Answer 1

Explanation:

Let firsr resistance is R1= 2 ohm

second resistance is R2 = 3 ohm

let resultant resistance = R ohm

when it connected in parallel

$then \\ \frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} \\ \\ \frac{1}{R} = \frac{1}{2} + \frac{1}{3} \\ \\ \frac{1}{R} = \frac{3 + 2}{6} \\ \\ \frac{1}{R} = \frac{5}{6} \\ \\ R = \frac{6}{5} \\ R = 12 \: \: ohm$

Required Ans......

Answer 2

Total Resistance in parallel

1/R = 1/ R1 + 1/ R2

.

1/R = 1/ 2 + 1/ 3

1/R = 3 + 2/ 3×2

1/R = 5/6

R = 6/5

Therefore the resultant resistance = 6/5 ohm