Question

With 63g of oxalic acid how many litres of n/10 solution can be prepared

Answer 1

63/90=Vx1/10
V =7/3 lit

Answer 2

20 Litres of N/10 solution can be prepared with 63 g of oxalic acid.

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

$\text{Normality of solution}=\frac{\text{Number of gram equivalents} \times 1000}{\text{Volume of solution (in mL)}}$

Or,

$\text{Normality of solution}=\frac{\text{Given mass}}{\text{Equivalent mass}\times \text{Volume of solution in L}}$

$\text{Equivalent weight}=\frac{\text{Molecular weight}}{n}$

where,

n = basicity for acids = 2 (For $C_2O_4H_2$

$\text{Equivalent weight}=\frac{63g/mol}{2eq/mol}=31.5g/eq$

$0.1=\frac{63}{31.5g/eq\times xL}$

$x=20L$    

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