with 63gm of oxalic acid how many litres of N/10solution can be prepared plz answer this question to fast friends with steps
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the n/10 of 60 is answer is 6.3 gm
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The Formula of oxalic acid is H2C2O4.2H2O.
molecular weight (126 g/mol)
63g oxalic acid = 0.5mol
Oxalic acid is dibasic, n-factor (Basicity) = 2
Now, Normality = No. of moles / n-factor / Vol in liters
or 0.1 = 0.5/ 2 / Vol in liters
so answer is 2.5 liters
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molecular weight (126 g/mol)
63g oxalic acid = 0.5mol
Oxalic acid is dibasic, n-factor (Basicity) = 2
Now, Normality = No. of moles / n-factor / Vol in liters
or 0.1 = 0.5/ 2 / Vol in liters
so answer is 2.5 liters
pls mark as brainliest pls
dipansu09:
pls mark as brainliest pls
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