Question

with a convex mirror when the object kept at a distance of 30 cm from the mirror at the image is formed at a distance of 10 cm from the mirror what will be the change in the image distance it object distance is doubled please give me answer in sum​

Answer 1

Answer:

u= 30

v= 10

f= ?

Explanation:

1/f = 1/u +1/v

= 1/-30 + 1/10

= 10+-30/-300

= -20/-300

-1/-15

=1/5

= f= +15

if u = -60 cm, v=?

1/f =1/u + 1/v

1/+15=1/-60+1/v

1/+15 = 1/-60 + 1/v

1/v = 1/15+1/60

= 60+5/900

=75/900

=1/12

V=12

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Answer 2

Explanation:

Hope it helps you...

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