Question

With an average acceleration of -1.2 m/s2, how LONG will it take a cyclist to bring a bicycle with an initial speed of 6.5 m/s to a complete stop?

Answer 1

Initial velocity of the cyclist = 6.5 m/s

At the end, the cyclist is coming to stop.

Hence, the final velocity of cyclist = 0 m/s

Average acceleration of the cyclist = -1.2 $\(\frac{m}{s^2}\)$

Let the time taken to come to stop be t.

Now, using the first equation of motion

$v_f = v_i + at$

$\(0 = 6.5 - 1.2 \times t\)$

$\( t = \frac{6.5}{1.2}\)$

t = 5.42 s

Hence, the time taken to come to stop is 5.42 s