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Question no 7
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Diagonal of a cube=a√3
Diagonal given =12√3
=> a√3=12√3=> a =12
=> Vol = >a^3 => 12^3 => 1728
the cubes are in ratio 3:4:5
let the edges be 3x, 4x, 5x
therefore volumes of the three cubes = volume of the full cube
(3x)^3+(4x)^3+(5x)^3
= 27+64+125 x^3
=216x^3=1728
=> x^3= 1728/216=8
=> x =2
therefore the three cubes edges are 3*2=6cm,
4*2=8cm
5*2=10cm
thank u hope it helped u!
Diagonal given =12√3
=> a√3=12√3=> a =12
=> Vol = >a^3 => 12^3 => 1728
the cubes are in ratio 3:4:5
let the edges be 3x, 4x, 5x
therefore volumes of the three cubes = volume of the full cube
(3x)^3+(4x)^3+(5x)^3
= 27+64+125 x^3
=216x^3=1728
=> x^3= 1728/216=8
=> x =2
therefore the three cubes edges are 3*2=6cm,
4*2=8cm
5*2=10cm
thank u hope it helped u!
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