with diagram derive an expression for magnification for compound microscope
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what u want, take it from this pic....
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(See fig 1st)
It is used for observing magnified images of objects. It is consists of a converging lens of small focal length.
Magnifying Power
(i) When final image is formed at least distance of distinct vision (D), then M=1+d/f
where, f= focal length of the lens.
(ii) When final image is formed at infinity, then M = D/f
(See fig. 2nd)
It is a combination of two convex lenses called objective lens and eye piece separated by a distance. Both lenses are of small focal lengths but fo < fe, where fo and feare focal lengths of objective lens and eye piece respectively
Magnifying Power
M = vo / uo {1 + (D/fo)
Where vo= distance of image, formed by objective lens and
uo = distance of object from the objective
(ii) When final image is formed at infinity, then
M = vo/uo . D/fe
(See fig. 3rd)
It is also a combination of two lenses, called objective lens and eye piece, separated by a distance. It is used for observing distinct images of heavenly bodies like stars, planets etc
Magnifying Power
(i) When final image is formed at least distance of distinct vision (D), then M = fo/fe {1+ (D/fe)} where foand fe are focal lengths of objective and eyepiece respectively.
Length of the telescope (L) = (fo + ue)
where, ue = distance of object from the eyepiece.
(ii) When final image is formed at infinity, then M = fo/fe
Length of the telescope (L) = fo + fe
For large magnifying power of a telescope fo should be large and feshould be small.
For large magnifying power of a microscope; fo < fe should be small.
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